An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude:

  • Option 1)

    \frac{\mu_0ne}{2\pi r}

  • Option 2)

    \frac{\mu_0n^{2}e}{r}

  • Option 3)

    \frac{\mu_0ne}{2r}

  • Option 4)

    Zero

 

Answers (1)

As we discussed

Magnetic field due to cCrcular Current Carrying arc -

B=frac{mu_{o}}{4pi}:frac{2pi i}{r}=frac{mu_{o}i}{2r}

- wherein

 

 current 1=\frac{e}{t}=1=\frac{e}{\left ( \frac{2\pi }{w} \right )}=\frac{we}{2\pi }=\frac{\left ( 2\pi x \right )e}{2\pi }

1= ne

at the centre of current carrying circular coil

B=\frac{\mu _{0}}{2r}=\frac{\mu _{0}n_{e}}{2r}


Option 1)

\frac{\mu_0ne}{2\pi r}

Option 2)

\frac{\mu_0n^{2}e}{r}

Option 3)

\frac{\mu_0ne}{2r}

Option 4)

Zero

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