The correct geometry and hybridization for XeF4 are

  • Option 1)

    octahedral, sp3d2

  • Option 2)

    trigonal bipyramidal, sp3d

  • Option 3)

    planar triangle, sp3d3

  • Option 4)

    square planar, sp3d2

 

Answers (1)

As we learnt in 

Dettermination of shape of molecules using VSEPR Theory -

calculate \:X

X=(No.\;of\:valence\:electrons\:of\:central\:atom\:)+(No.\:of\:other\:atom\:)+(Negative\:charge\:on\:the\:molecule)-(Positive\:charge\:on\:the\:molecule)

-

Shape of molecules -

-

 sp^{3}d^{2}  hybridisation(octahedrai geometry square planar shape).

 


Option 1)

octahedral, sp3d2

This is incorrect option

Option 2)

trigonal bipyramidal, sp3d

This is incorrect option

Option 3)

planar triangle, sp3d3

This is incorrect option

Option 4)

square planar, sp3d2

This is correct option

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