Q

# I have a doubt, kindly clarify. When a block of mass M is suspended by a long wire of length L , The length of the wire becomes (L+l ) . The elastic potential energy stored in the extended wire is :

When a block of mass M is suspended by a long wire of length L , The length of the wire becomes (L+l ) . The elastic potential energy stored in the extended wire is :

• Option 1)

Mgl

• Option 2)

MgL

• Option 3)

1/2 Mgl

• Option 4)

1/ MgL

Views

$we \ \ have \ M_1 , L_1 , \Delta L = l \\\\ E = 1/2 \times F \times ( \Delta L) \\\\ \Rightarrow E = 1/2 \times Mg \times l$

Option 1)

Mgl

Option 2)

MgL

Option 3)

1/2 Mgl

Option 4)

1/ MgL

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