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I have a doubt, kindly clarify. When a block of mass M is suspended by a long wire of length L , The length of the wire becomes (L+l ) . The elastic potential energy stored in the extended wire is :

When a block of mass M is suspended by a long wire of length L , The length of the wire becomes (L+l ) . The elastic potential energy stored in the extended wire is : 

 

  • Option 1)

    Mgl 

  • Option 2)

    MgL 

  • Option 3)

    1/2 Mgl

  • Option 4)

    1/ MgL

Answers (1)
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we \ \ have \ M_1 , L_1 , \Delta L = l \\\\ E = 1/2 \times F \times ( \Delta L) \\\\ \Rightarrow E = 1/2 \times Mg \times l 


Option 1)

Mgl 

Option 2)

MgL 

Option 3)

1/2 Mgl

Option 4)

1/ MgL

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