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A transformer having efficiency of 90% is working on 200V and 3kW power supply. If the current in the secondary coil is 6A, the voltage across the secondary coil and the current in the primary coil respectively are:

  • Option 1)

    300V, 15A

  • Option 2)

    450V, 15A

  • Option 3)

    450V, 13.5A

  • Option 4)

    600V, 15A

 

Answers (1)

best_answer

 

Efficiency of transformer -

\eta % = \frac{P_{out}}{P_{in}}\times 100=\frac{V_{s}\, {i}'_{s}}{V_{P}\, {i}'P}\times 100

-

 

 power supply=3KW

at 90% efficiency power in secondary coil is = 2.7KW

\Rightarrow V_{s}I_{s}=2.7KW\Rightarrow V_{s}=\frac{2.7\times 10^{3}}{6}V

V_{s}=450V

Current in primary coil I_{p}=\frac{power}{voltage}

I_{p}=\frac{3000}{200}A=15A


Option 1)

300V, 15A

This is incorrect option

Option 2)

450V, 15A

This is correct option

Option 3)

450V, 13.5A

This is incorrect option

Option 4)

600V, 15A

This is incorrect option

Posted by

prateek

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