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  • I need help with The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:

The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:

  • Option 1)

    2

  • Option 2)

    1

  • Option 3)

    4

  • Option 4)

    0.5

 

Answers (1)

best_answer

Last line of lymen series means transition from n=\infty \rightarrow n=1 

Energy emitted due to transition of electron -

Delta E= Rhcz^{2}left ( frac{1}{n_{f}, ^{2}}-frac{1}{n_{i}, ^{2}} ight )

frac{1}{lambda }= Rz^{2}left ( frac{-1}{n_{i}, ^{2}}+frac{1}{n_{f}, ^{2}} ight )

- wherein

R= R hydberg: constant

n_{i}= initial state \n_{f}= final : state

 

 \frac{1}{\lambda _(lymen)} =Rz^2(1-\frac{1}{\infty^2 }) or \lambda _(lymen)=\frac{1}{Rz^2}

Last line of balrner series means transition from n=\infty \:to\: n=2

\frac{1}{\lambda (balmer)} =Rz^2(\frac{1}{4}-\frac{1}{\infty }) or \lambda (balmer)=\frac{4}{Rz^2}

\frac{\lambda (balmer)}{\lambda (lymer)}=4


Option 1)

2

Incorrect

Option 2)

1

Incorrect

Option 3)

4

Correct

Option 4)

0.5

Incorrect

Posted by

Plabita

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