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If at a point on boundary between two dielectric the electric field make angle  \theta_1  and  \theta_2  with the normal in media of permittivity \epsilon_1 and \epsilon_2  respectively, then which one of the relation is correct?

Option: 1

\frac{\tan \theta_1}{\tan \theta_2}=\frac{\epsilon_1}{\epsilon_2}


Option: 2

\frac{\tan \theta_1}{\tan \theta_2}=\frac{\epsilon_2}{\epsilon_1}


Option: 3

\frac{\sin \theta}{\sin \theta_2}=\frac{\epsilon_1}{\epsilon_2}


Option: 4

\frac{\sin \theta_1}{\sin \theta_2}=\frac{\epsilon_2}{\epsilon_1}


Answers (1)

best_answer

D_1 \cos \theta_1 =D_2 \cos \theta_2 \\
\epsilon_1 \epsilon _1 \cos \theta_1 =\epsilon_2 \epsilon _2 \cos \theta_2.................(2)

Tangential component of electric intensity is continuous across boundary -


E_1 \sin \theta_1=E_2 \sin \theta_1..............(1)

Divide (2) by (1)

\frac{\tan \theta_1}{\epsilon_1}=\frac{\tan \theta_2}{\epsilon_2} \\
\frac{\tan \theta_1}{\tan \theta_2}=\frac{\epsilon_1}{\epsilon_2}

Posted by

manish painkra

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