#### in a dihybrid cross between two heterozygous parents (AaBb AaBb), what is the probability of obtaining an offspring with the genotype AABb?Option: 1 $\frac{1}{8}$  Option: 2 $\frac{1}{16}$Option: 3 $\frac{1}{4}$Option: 4 $\frac{3}{16}$

In a dihybrid cross, the genotypes of the parents are AaBb. to determine the probability of obtaining an offspring with genotype AABb, we need to consider the segregation of alleles during gamete formation and their combination in the offspring.

For the genotype AABb, the possible combinations are AaBb, AaBb, AABb and AABb. Since the alleles segregate independently, the probability of obtaining an AABb genotype from each parent is $\frac{1}{2}$ for A and $\frac{1}{4}$ for B. Therefore the probability of obtaining AABb from both parents is $\frac{1}{2}\times \frac{1}{4}=\frac{1}{8}$.

However, we have two possible combinations, so we multiply the probability by 2 to consider both options. Therefore the final possibility is $2 \times \frac{1}{8}=\frac{1}{4}$.