Get Answers to all your Questions

header-bg qa

In a population of birds, the frequency of the dominant allele for feather color is 0.6. What is the population's expected frequency of heterozygous individuals, assuming Hardy-Weinberg equilibrium?

Option: 1

0.12


Option: 2

0.36


Option: 3

0.48

 


Option: 4

0.72


Answers (1)

best_answer

Applying the Hardy-Weinberg Equation, 

The frequency of the dominant allele is p = 0.6

The frequency of the recessive allele is q = 1 - p = 0.4.

The frequency of heterozygous individuals is 2pq, where p and q represent the frequencies of the dominant and recessive alleles, respectively.

Therefore, the expected frequency of heterozygous individuals in the population is 2 x 0.6 x 0.4 x 1000 = 480/1000 = 0.48.

Option 3 is the correct answer

Posted by

admin

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks