In a segment of DNA, the number of adenine bases is equal to the number of cytosine bases, with each being 120. Determine the total count of nucleotides within this DNA segment.
120
240
480
360
In the given DNA segment, the number of adenine (A) bases is equal to the number of cytosine (C) bases, with both being 120.
In DNA, each nucleotide consists of a base (A, C, G, or T) attached to a sugar and a phosphate group. Therefore, to determine the total count of nucleotides, we need to consider the contribution of all four bases.
Since Adenine (A) and Cytosine (C) are two of the four bases, and their combined count is 240 (120 + 120), we still need to account for the other two bases: Guanine (G) and Thymine (T).
Since DNA is double-stranded, Adenine (A) pairs with Thymine (T) and Cytosine (C) pairs with Guanine (G). Therefore, the number of Guanine (G) bases must also be 120 to maintain the base pairing rule.
Considering all four bases (A, T, C, and G), the total count of nucleotides in this DNA segment is obtained by summing the counts of each base, which is 120 + 120 + 120 + 120 = 480.
Hence, the correct answer is option 3.