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  • Light from a discharge tube containing hydrogen atoms falls on the surface of a piece of sodium. The kinetic energy of the fastest photoelectrons emitted from sodium is 0.73 eV. The work function f

Light from a discharge tube containing hydrogen atoms falls on the surface of a piece of sodium. The kinetic energy of the fastest photoelectrons emitted from sodium is 0.73 eV. The work function for sodium is 1.82 eV.

Option: 1

3 & 1


Option: 2

3 & 2


Option: 3

4 & 1


Option: 4

4 & 2


Answers (1)

best_answer

These photons (whose energy is 2.55 eV) are by hydrogen atoms.

\mathrm{\begin{aligned} & \text { As }(\text { I.E. })_H=13.6 \mathrm{eV} \text {, hence } E_1^H=-(\text { I.E. })_H= \\ & -13.6 \mathrm{eV} \end{aligned}}

The energy of higher levels is given by

\mathrm{\begin{aligned} & E_n^H=\frac{E_1^H}{n^2} \\ & \text { Hence, } \quad E_2^H=-\frac{13.6}{4}=-3.4 \mathrm{eV}, E_3^H=-\frac{13.6}{9} \\ & \quad=-1.5 \mathrm{eV} \text { and } E_4^H=-\frac{13.6}{16}=-0.85 \mathrm{eV} \end{aligned}}

The energy of the emitted photon is 2.55 eV.
\mathrm{\text { Now } E_4^H-E_2^H=-0.85 \mathrm{eV}-(3.4 \mathrm{eV})=2.55 \mathrm{eV} \text {. }}
Thus the quantum numbers of two levels involved
in the emission of photon of energy 2.55 eV are 4
and 2.

Posted by

sudhir.kumar

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