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Metal 'O' reacts with oxygen to form a compound ' P ' which is a blue solid. Compound ' P ' when dissolved in water, forms a blue solution. The metal 'O' is

Option: 1

\begin{aligned} & \mathrm{Zn} \\ \end{aligned}


Option: 2

\begin{aligned} & \mathrm{Cu} \\ \end{aligned}


Option: 3

\begin{aligned} & \mathrm{Fe} \\ \end{aligned}


Option: 4

\begin{aligned} & \mathrm{Mg} \end{aligned}


Answers (1)

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When copper (\mathrm{Cu}) reacts with oxygen \left(\mathrm{O}_2\right), it forms a compound 'P' known as copper oxide \text{(CuO)}. Copper oxide is a blue solid.
The reaction can be represented as:
2 \mathrm{Cu}+\mathrm{O}_2 \rightarrow 2 \mathrm{CuO}

Compound ' \text{P} ' mentioned in the question is copper oxide \text{(CuO)}.

When copper oxide \text{(CuO)} is dissolved in water, it forms a blue solution. The presence of the copper ions \left(C u^{2+}\right) in the solution gives it a characteristic blue color.
\mathrm{CuO}(s)+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{Cu}^{2+}(a q)+\mathrm{OH}^{-}(a q)

Therefore, based on the given information, the metal 'O' is copper \text{(Cu)}.

 

Posted by

himanshu.meshram

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