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  • Need clarity, kindly explain! A refrigerator works between 4°C and 30°C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is:(Take 1 cal = 4.2 j

A refrigerator works between 4°C and 30°C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is:

(Take 1 cal = 4.2 joules)

  • Option 1)

    2.365 W

  • Option 2)

    23.65 W

  • Option 3)

    236.5 W

  • Option 4)

    2365 W

 

Answers (1)

As we learnt in 

Coefficient of performance (beta) -

eta = frac{Q_{2}}{Q_{1}-Q_{2}}= frac{T_{2}}{T_{1}-T_{2}}
 

- wherein

T_{1}> T_{2}

For a perfect refrigerator eta ightarrow infty

 

 Q_{2}=600 cal/sec

=600\times 4.2 \: J/s = 2520 W

\beta =\frac{T_{2}}{T_{1}-T_{2}}=\frac{Q_{2}}{W}

or    \frac{277}{303-277}=\frac{2520}{W}

or    W=\frac{2520\times 26}{277}=236.5W

Correct option is 3.


Option 1)

2.365 W

This is incorrect option

Option 2)

23.65 W

This is incorrect option

Option 3)

236.5 W

This is correct option

Option 4)

2365 W

This is incorrect option

Posted by

Vakul

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