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  • Need clarity, kindly explain! An electron is moving in a circular path under the influence of a transversemagnetic field of 3.57 x 10-2 T. If the value of e/m is 1.76 x 1011C/kg, thefrequency of revolution of the electron is

An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 x 10-2 T. If the value of e/m is 1.76 x 1011 C/kg, the frequency of revolution of the electron is

  • Option 1)

    1 GHz

  • Option 2)

    100 MHz

  • Option 3)

    62.8 MHz

  • Option 4)

    6.28 MHz

 

Answers (1)

best_answer

As we discussed

Radius of charged particle -

r=frac{mv}{qB}=frac{P}{qB}=frac{sqrt{}2mk}{qB}=frac{1}{B}sqrt{}frac{2mV}{q}

-

 

 

Frequency of charged particle -

F=frac{1}{T}=frac{qB}{2pi m}

-

 

 \frac{e}{m}=1.76\times 10^{11} CKg^{-1}

Frequency = v=\frac{1}{t}= \frac{v}{2\pi r}

\frac{mv^{2}}{r}=ev_{B}\Rightarrow \frac{v}{r}=\frac{e_{B}}{m}

v=\frac{1}{2\pi }\frac{e_{B}}{m}=\frac{1}{2\times 3.14}\times 1.76\times 10^{11}\times 3.57\times 10^{-2}

v=10^{9} H_{z}= 1 GH_{z}


Option 1)

1 GHz

Correct option

Option 2)

100 MHz

Incorrect option

Option 3)

62.8 MHz

Incorrect option

Option 4)

6.28 MHz

Incorrect option

Posted by

divya.saini

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