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A 250-turn rectangular coil of length 2.1cm and width 1.25cm carries a current of 85\mu A and subjected to magnetic field of strength 0.85T. Work done for rotating the coil by 180^{o} against the torque is

  • Option 1)

    4.55\mu j

  • Option 2)

    2.3\mu j

  • Option 3)

    1.15\mu j

  • Option 4)

    9.1\mu j

 

Answers (1)

As we learnt 

Work done by current carrying coil -

W=MB(1-cos 	heta )

-

 

 work done = NIAB (1-\cos \Theta)

N = 250, A= L X b    2.1 cm X 1.25 cm

 I= 85 \mu A ,      B= 0.85 T ,     \theta =180^{\circ}

w=9.1 \mu j


Option 1)

4.55\mu j

Incorrect Option

Option 2)

2.3\mu j

Incorrect Option

Option 3)

1.15\mu j

Incorrect Option

Option 4)

9.1\mu j

Correct Option

Posted by

Vakul

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