Mechanism of a hypothetical reaction X2 + Y2 \rightarrow 2XY is given below :

(i) X2 \rightarrow X + X (fast)

(ii) X + Y2 \leftrightharpoons XY + Y (slow)

(iii) X + Y \rightarrow XY (fast)

The overall order of the reaction will be :

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    0

  • Option 4)

    1.5

 

Answers (1)

As learnt

Rate of Law = Dependence of Rate on Concentration -

The representation of rate of a reaction in terms of concentration of the reactants is known as Rate Law

or

The Rate Law is the expression in which reaction rate is given in terms of molar concentration of reactants with each term raised to some power, which may/maynot be equal to stoichiometric of the reacting species in a balanced chemical equation 

- wherein

Formula: aA+bB\rightarrow cC+dD

              Rate=\frac{dR}{dT}

              =\alpha [A]^{x}.[B]^{y}

             =k[A]^{x}.[B]^{y}

 K= rate constant

 

 The given reaction

X_{2\rightleftharpoons }X+X (Fast)

X+Y_{2}\rightarrow XY+Y (slow)

Slow step in the reaction is rate determining step

\therefore Rate =K[x]\: [y_{2}]-----------------------(1)

Equilibrium constant for fast step

K=\frac{[x]^{2}}{[X_2]}

\therefore [X]=\sqrt{K[X_2]}

Substituting [X] in the first step will give

Rate = K.\sqrt{K[X_2]}.[Y_2]

=K{}'.[X_2]^{1/2}.[Y_2]

\therefore Order of reaction = 1+\frac{1}{2}=3/2

 


Option 1)

1

This option is incorrect

Option 2)

2

This option is incorrect

Option 3)

0

This option is incorrect

Option 4)

1.5

This option is correct

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