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  • Need explanation for: - Electromagnetic Induction and alternative Currents - NEET-2

An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3\Omega, the phase difference between the applied voltage and the current in the circuit is

  • Option 1)

    \frac{\pi}{6}

  • Option 2)

    \frac{\pi}{4}

  • Option 3)

    \frac{\pi}{2}

  • Option 4)

    zero

 

Answers (1)

 

Quality factor (Q factor) -

It define sharpness of i- u curve at resonance. When Q factor is large , the sharpness of resonance curve is more and vice versa.

-

 

 phase difference \Phi =cos^{-1}\frac{R}{Z}

\Phi =cos^{-1}\left ( \frac{3}{\sqrt{3^{2}+3^{2}}} \right )=\cos ^{-1}\left ( \frac{1}{\sqrt{2}} \right )

\Phi =\frac{\pi}{4}


Option 1)

\frac{\pi}{6}

This is incorrect option

Option 2)

\frac{\pi}{4}

This is correct option

Option 3)

\frac{\pi}{2}

This is incorrect option

Option 4)

zero

This is incorrect option

Posted by

subam

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