A 800 turn coil  of  effective area 0.05 m ^ 2  is kept perpendicular to a magnetic field 5 \times 10 ^{-5} T . When the plane of the coil is rotated by 90 around  any of its coplanar axis in 0.1 s , the emf induced in the coil will be : 

 

  • Option 1)

    2 V 

  • Option 2)

    0.2 V 

  • Option 3)

    0.0002 V 

  • Option 4)

    0.02 V 

 

Answers (1)

N = 800 

 A = 0.05 m ^ 2

  B = 5 \times 10 ^{-5} T

case 1    B and A are parallel 

So \phi _1=BAN

case 2 B and A are perpendicular 

So \phi _2=0

emf = d \phi / dt = \frac{NBA \sin \omega t }{t} - 0 \\\\ emf= \frac{800 \times 5 \times 10 ^{-5}\times \sin 90 }{0.1} \\\\ = 0.02 V


Option 1)

2 V 

Option 2)

0.2 V 

Option 3)

0.0002 V 

Option 4)

0.02 V 

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