Q

# Need explanation for: - Electromagnetic Induction and alternative Currents - NEET-3

A 800 turn coil  of  effective area $0.05 m ^ 2$  is kept perpendicular to a magnetic field $5 \times 10 ^{-5} T$ . When the plane of the coil is rotated by 90 around  any of its coplanar axis in 0.1 s , the emf induced in the coil will be :

• Option 1)

2 V

• Option 2)

0.2 V

• Option 3)

0.0002 V

• Option 4)

0.02 V

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N = 800

$A = 0.05 m ^ 2$

$B = 5 \times 10 ^{-5} T$

case 1    B and A are parallel

So $\phi _1=BAN$

case 2 B and A are perpendicular

So $\phi _2=0$

$emf = d \phi / dt = \frac{NBA \sin \omega t }{t} - 0 \\\\ emf= \frac{800 \times 5 \times 10 ^{-5}\times \sin 90 }{0.1} \\\\ = 0.02 V$

Option 1)

2 V

Option 2)

0.2 V

Option 3)

0.0002 V

Option 4)

0.02 V

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