Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Need explanation for: The hybridization involved in complex [Ni(CN)4]2-is: (At. No.Ni = 28)

The hybridization involved in complex [Ni(CN)4]2-is:     (At. No.Ni = 28)

  • Option 1)

    dsp2

  • Option 2)

    sp3

  • Option 3)

    d2sp2

  • Option 4)

    d2sp3

 

Answers (1)

best_answer

As we discused

Hybridisation -

sp3d2 - square bipyramidal or octahedral 

d2sp3 - octahedral 

sp3 - tetradedral 

dsp2 - square planar

- wherein

sp3d2 - outer complex

d2sp3 - inner complex

sp3 - [Ni(Cl)_{4}]^{2-}

dsp2 - [Pt(CN)_{4}]^{2-}

 

 In [Mi\left ( CN \right )_{4}]^{2-} The oxidation state of Mi is +2 and CN^{-} is a strong field ligand which can pain the unpaired electron of Ni^{2+}

 


Option 1)

dsp2

This is correct option

Option 2)

sp3

This is incorrect option

Option 3)

d2sp2

This is incorrect option

Option 4)

d2sp3

This is incorrect option

Posted by

Aadil

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG city intimation slip likely today at exams.nta.ac.in/NEET; barred item at exam centre
anam-khan

NEET UG 2024 exam city slip soon; admit card updates
anam-khan

NEET UG 2024 application correction window closes today; editable details, fees

Latest Question