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  • Need explanation for: Three identical spherical shells, each of mass m and radius r are placed as shown in figure. Consider an axis XX' which is touching to two shells and passing through diameter of third shell.Moment of inertia of the system co

Three identical spherical shells, each of mass m and radius r are placed as shown in figure. Consider an axis XX' which is touching to two shells and passing through diameter of third shell.

Moment of inertia of the system consisting of these three spherical shells about XX' axis is :

 

  • Option 1)

    \frac{16}{5} mr^{2}

  • Option 2)

    4 mr^{2}

  • Option 3)

    \frac{11}{5} mr^{2}

  • Option 4)

    3 mr^{2}

 

Answers (1)

best_answer

As we learnt in 

Moment of inertia for system of particle -

I= m_{1}r_{1}^{2}+m_{2}r_{2}^{2}+.........m_{n}r_{n}^{2}

dpi{100} = sum_{i=1}^{n}: m_{i}r_{i}^{2}

 

- wherein

Applied when masses are placed discretely.

 

 

I=I_{1}+I_{2}+I_{3}

I=\frac{1}{2}MR^{2}+\frac{3}{2}MR^{2}+\frac{3}{2}MR^{2}

I=\frac{7}{2}MR^{2}


Option 1)

\frac{16}{5} mr^{2}

Incorrect

Option 2)

4 mr^{2}

Correct

Option 3)

\frac{11}{5} mr^{2}

Incorrect

Option 4)

3 mr^{2}

Incorrect

Posted by

Aadil

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