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Which of the following statements is correct for the spontaneous adsorption of a gas?

  • Option 1)

    \Delta S is negative and, therefore, \Delta H should be highly positive.

  • Option 2)

    \Delta S is negative and therefore, \Delta H should be highly negative.

  • Option 3)

    \Delta S is positive and, therefore, \Delta H should be negative.

  • Option 4)

    \Delta S is positive and, therefore, \DeltaH should also be highly positive.

 

Answers (1)

As we learned in concept

We have \Delta G=\Delta H-T\Delta S

for a spontanous process, \Delta G=-\omega

if \Delta s=-\omega as it is in the case of adsorption then to make \Delta G=-\omega\Delta H would have to be highly -\omega


Option 1)

\Delta S is negative and, therefore, \Delta H should be highly positive.

Option is incorrect

Option 2)

\Delta S is negative and therefore, \Delta H should be highly negative.

Option is correct

Option 3)

\Delta S is positive and, therefore, \Delta H should be negative.

Option is incorrect

Option 4)

\Delta S is positive and, therefore, \DeltaH should also be highly positive.

Option is incorrect

Posted by

Sabhrant Ambastha

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