Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • On a smooth inclined plane at 30 degrees with the horizontal , a thin current carrying metallic rod is placed parallel to the ho

On a smooth inclined plane at 30 degrees with the horizontal , a thin current carrying metallic rod is placed parallel to the horizontal groundc.The plane is located in a uniform magnetic field of 0.15T in the vertical direction . For what value of current can the rod remain stationery? The mass per unit length of the rod is 0.03kg/m

Answers (1)

F upward = Bi L cos 30 = BiL * sqrt (3) / 2

 

F downward the gravity = mg sin 30 = mg/2

 

for equilibrium

 

F upward   = F downward

 

i = mg / BL * sqrt (3)

 

i = 0.03 * 10 / 0.15 * 1 * 1.732

 

i = 1.15 A

Posted by

Safeer PP

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2024 application correction facility ends today; exam pattern, marking scheme
anam-khan

NTA re-opens NEET UG correction window 2024; update photographs till April 26
anam-khan

NEET UG 2024 exam city slip out at neet.ntaonline.in; over 25 lakh candidates to appear

Latest Question