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Oxidation states of the metal in the minerals malachite and azurite, respectively are:

Option: 1

II, IV in malachite and II in azurite


Option: 2

II, IV in malachite and IV in azurite


Option: 3

IV in malachite and II, IV in azurite


Option: 4

II in malachite and II, IV in azurite


Answers (1)

best_answer

Malachite \left(\mathrm{Cu}_2 \mathrm{CO}_3(\mathrm{OH})_2\right) is a mineral that contains copper (Cu). In malachite, copper has two different oxidation states: II and IV. The copper atoms in malachite exist in the +2 oxidation state \left(\mathrm{Cu}^{2+}\right) and the +4 oxidation state \mathrm{\left(C u^{4+}\right)}. This is due to the presence of both cupric \left(\mathrm{Cu}^{2+}\right) and cuprous (\mathrm{Cu+}) ions in the mineral structure.

Azurite \left(\mathrm{Cu}_3\left(\mathrm{CO}_3\right)_2(\mathrm{OH})_2\right) is another mineral that contains copper. In azurite, copper exists only in the +2 oxidation state \left(\mathrm{Cu}^{2+}\right). The copper atoms in azurite are all in the cupric \left(\mathrm{Cu}^{2+}\right) form.

Therefore, the correct statement regarding the oxidation states of the metal in malachite and azurite is that malachite contains copper in the oxidation states II and IV, while azurite contains copper in the oxidation state IV.

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