Two point charges A and B , having charges Q and - Q respectively , are placed at a certain distance apart ad force acting between them is F . If 25 % charge of A is transferres to B , then force between he charges  becomes : 

 

  • Option 1)

  • Option 2)

    9F/16

  • Option 3)

    16F/9

  • Option 4)

    4F/3

 

Answers (1)

F = \frac{-KQ^2}{d^2}\\\\ F' = \frac{-k \left ( \frac{3Q}{4} \frac{3Q}{4} \right )}{d^2}\\\\ \frac{F}{F'} = \frac{1 }{\left ( \frac{9}{16} \right )} = 16/9 \\\ F' = 9 F /16

 


Option 1)

Option 2)

9F/16

Option 3)

16F/9

Option 4)

4F/3

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