Which of the following is correct option for free expansion of an ideal gas under adiabatic condition ?

  • Option 1)

    q=0,\:\Delta T\neq 0,w=0

  • Option 2)

    q\neq0,\:\Delta T= 0,w=0

  • Option 3)

    q=0,\:\Delta T= 0,w=0

  • Option 4)

    q=0,\:\Delta T< 0,w\neq0

 

Answers (1)

 

First law of Thermodynamics -

Energy of universe is always conserved or total energy of an isolated system is always conserved

\Delta E= q + W


 

- wherein

\Delta E= Internal Energy

q= Heat

W= work

 

 

Adiabatic Process -

Heat exchange between system and surrounding is zero i.e. q= 0
 

- wherein

\Delta E= q+w

q= 0

\Delta E=w

 

 For free expansion, since P_e_x_t=0

So, Work done =0

For adiabatic condition, q=0

\Delta v=0

\Delta T=0

 

 


Option 1)

q=0,\:\Delta T\neq 0,w=0

Incorrect option

Option 2)

q\neq0,\:\Delta T= 0,w=0

Incorrect option

Option 3)

q=0,\:\Delta T= 0,w=0

Correct option

Option 4)

q=0,\:\Delta T< 0,w\neq0

Incorrect option

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