Which of these statements about [Co(CN)6]3- is true?

  • Option 1)

    [Co(CN)6]3 - has four unpaired electrons and will be in a high-spin configuration.

  • Option 2)

    [Co(CN)6]3 - has no unpaired electrons and will be in a high-spin configuration.

  • Option 3)

    [Co(CN)6]3 - has no unpaired electrons and will be in a low-spin configuration.

  • Option 4)

    [Co(CN)6]3 - has four unpaired electrons and will be in a low-spin configuration.

 

Answers (1)

As we discussed in the concept

Inner sphere complex -

Complexes in which (n-1)d orbitals are used in hyberdisation.

- wherein

For example: d^{2} sp^{3} hybrid \left [ Fe\left ( CN \right )_{6} \right ]

 

 

Strong Field Ligand -

These are the ligands which pair the electron in inner d-orbital and makes required d-orbitals empty/available. 

- wherein

For example: CO, CN etc

 

 CN^-  is a strong field ligand which pairs the all unpaired electrons of Co^{3+}\: in\:[Co(CN)_6]^{3-} which results no unpaired electron in the Co^{3+} and it form low spin complex.


Option 1)

[Co(CN)6]3 - has four unpaired electrons and will be in a high-spin configuration.

Incorrect

Option 2)

[Co(CN)6]3 - has no unpaired electrons and will be in a high-spin configuration.

Incorrect

Option 3)

[Co(CN)6]3 - has no unpaired electrons and will be in a low-spin configuration.

Correct

Option 4)

[Co(CN)6]3 - has four unpaired electrons and will be in a low-spin configuration.

Incorrect

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