Which of these statements about [Co(CN)6]3- is true?
[Co(CN)6]3 - has four unpaired electrons and will be in a high-spin configuration.
[Co(CN)6]3 - has no unpaired electrons and will be in a high-spin configuration.
[Co(CN)6]3 - has no unpaired electrons and will be in a low-spin configuration.
[Co(CN)6]3 - has four unpaired electrons and will be in a low-spin configuration.
As we discussed in the concept
Inner sphere complex -
Complexes in which (n-1)d orbitals are used in hyberdisation.
- wherein
For example:
Strong Field Ligand -
These are the ligands which pair the electron in inner d-orbital and makes required d-orbitals empty/available.
- wherein
For example: CO, CN etc
is a strong field ligand which pairs the all unpaired electrons of which results no unpaired electron in the and it form low spin complex.
Option 1)
[Co(CN)6]3 - has four unpaired electrons and will be in a high-spin configuration.
Incorrect
Option 2)
[Co(CN)6]3 - has no unpaired electrons and will be in a high-spin configuration.
Incorrect
Option 3)
[Co(CN)6]3 - has no unpaired electrons and will be in a low-spin configuration.
Correct
Option 4)
[Co(CN)6]3 - has four unpaired electrons and will be in a low-spin configuration.
Incorrect