Get Answers to all your Questions

header-bg qa

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

  • Option 1)

    2.8

  • Option 2)

    3.0

  • Option 3)

    1.4

  • Option 4)

    4.4

 

Answers (1)

best_answer

As we learnt that

Number of Moles -

No of moles = given mass of substance/ molar mass of substance

-

 

 HCOOH\xrightarrow[]{H_{2}SO_{4}} CO + H_{2}O

 

\frac{2.3}{46} = \frac{1}{20}                     \frac{1}{20} mole       (H2O is absorbed by H2SO4)

        

H_{2}C_{2}O_{4}\xrightarrow[]{H_{2}SO_{4}} CO + CO_{2} + H_{2}O

\frac{4.5}{90} = \frac{1}{20}                \frac{1}{20} mole      (CO2 is absorbed by KOH and H2O   by H2SO4)

Total moles of CO is 0.1 mole i.e. 2.8 gm.


Option 1)

2.8

This is correct.

Option 2)

3.0

This is incorrect.

Option 3)

1.4

This is incorrect.

Option 4)

4.4

This is incorrect.

Posted by

divya.saini

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks