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  • Please,please help me - d and f Block Elements - NEET

Acidified K_{2}Cr_{2}O_{7} solution turns green when Na_{2}SO_{3} is added to it. This is due to the formation of:

  • Option 1)

    Cr_{2}(SO_{4})_{3}

  • Option 2)

    CrO_{4}^{2-}

  • Option 3)

    Cr_{2}(SO_{3})_{3}

  • Option 4)

    CrSO_{4}

 

Answers (1)

As learnt in concept

'd' Block in periodic table -

In periodic table, the 'd' block elements are present between s and p block elements by the position and the three rows of transition metal are  3d 4d 5d, the 6d series is still incomplete.

- wherein

21^{Sc}\Rightarrow 3d^1\:4s^2

39^{Y}\Rightarrow 4d^1\:5s^2

57^{La}\Rightarrow 5d^1\:6s^2

89^{Ac}\Rightarrow 6d^1\:7s^2

 

 The reaction proceeds as follows:

K_{2}Cr_{2}O_{7}+3Na_{2}SO_{3}+4H_{2}SO_{4}\rightarrow 3Na_{2}SO_{4}+K_{2}SO_{4}+Cr_{2}(SO_{4})_{3}+4H_{2}O

The green color is due to formation of chromium (III) sulphate


Option 1)

Cr_{2}(SO_{4})_{3}

This solution is correct 

Option 2)

CrO_{4}^{2-}

This solution is incorrect 

Option 3)

Cr_{2}(SO_{3})_{3}

This solution is incorrect 

Option 4)

CrSO_{4}

This solution is incorrect 

Posted by

Vakul

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