An electron is accelerated through a potential diffrence of 10000 V . Its debrogile wavelength is : 

( m_ e ) = 9 \times 10 ^{-31} Kg

  • Option 1)

    12.2 \times 10 ^{-13} m

  • Option 2)

    12.2 \times 10 ^{-12} m

  • Option 3)

    12.2 \times 10 ^{-14} m

  • Option 4)

    12.2 nm 

Answers (1)

\lambda = \frac{h }{\sqrt {2 m qv} } \\\\ \frac{6.6 \times 10 ^{-3 4}}{\sqrt {2 \times 9 \times 10 ^{-31} \times 1.6 \times 10 ^{-19}\times 10000}} \\\\ 12.2 \times 10 ^{-12} m


Option 1)

12.2 \times 10 ^{-13} m

Option 2)

12.2 \times 10 ^{-12} m

Option 3)

12.2 \times 10 ^{-14} m

Option 4)

12.2 nm 

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