# What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO3 is mixed with 50 mL of 5.8% NaCl solution ?(Ag = 107.8, N = 14, O = 16, Na = 23, CI = 35.5) Option 1) 28 g Option 2) 3.5 g Option 3) 7 g Option 4) 14 g

As we discussed in

Mass percent of solution -

Mass percent = ((mass of solute)/(mass of solution) ) X 100

- wherein

it is mass of solute present in 100 gram solution.

16.9% solution of AgNO3 means 16.9g AgNO3 in 100ml solution.

50ml of solution contains

Similarly, 100ml of other solution contains 5.8g NaCl

50ml of other solution contains 2.9g NaCl

Mol of AgNO3 =

Mol of NaCl =

AgNO3 + NaCl Ag0Cl + Na0NO3

0.049        0.049      0.049       0.049

0               0

Mass of AgCl = 0.049 x Molar mass of AgCl

= 0.049 x 143.5 = 7g

Option 1)

28 g

This option is incorrect.

Option 2)

3.5 g

This option is incorrect.

Option 3)

7 g

This option is correct.

Option 4)

14 g

This option is incorrect.

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