Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Rate of increment of energy in an inductor with time in series LR circuit getting charge with battery of e.m.f. E is best represented by: [ inductor has initially zero current ]
Option: 1

Option: 2

Option: 3

Option: 4

Answers (1)

best_answer

Energy stored in the magnetic field of the inductor -

$U= \frac{1}{2}LI^{2}$

Rate of increment of energy in inductor $=\frac{dU}{dt}=\frac{d}{dt}\left ( \frac{1}{2}Li^{2} \right )=Li\frac{di}{dt}$

Current in the inductor at time t is:

$i=i_{0}(1-e^{-\frac{t}{\tau }})$ and $\frac{di}{dt}=\frac{i_{0}}{\tau }e^{-\frac{t}{\tau }}$

$\therefore \frac{dU}{dt}=\frac{Li_{0}^{2}}{\tau }e^{-\frac{t}{\tau }}\left ( 1-e^{-\frac{t}{\tau }} \right )$

$\frac{dU}{dt}=0$ at $t=0$

and $t=\infty$

Hence E is best represented by :

Posted by

rishi.raj

View full answer

NEET 2024 Most scoring concepts

Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Bihar NEET PG 2024 stray vacancy round registration starts tomorrow; schedule out

anam-khan

NEET UG must for foreign MBBS graduates to obtain eligibility certificate; NMC regulations explained

anam-khan

Top private medical colleges in India accepting NEET UG score for admission; NIRF rankings

Latest Question