Q

# Solve! A compound is formed by cation C and anion A. The Anions form hexagonal close packed lattice and the cations occupy 75% of the octahedral void. The formula of the compound is

A compound is formed by cation C and anion A. The Anions form hexagonal close packed lattice and the cations occupy 75% of the octahedral void. The formula of the compound is

• Option 1)

$C_2A_3$

• Option 2)

$C_3A_2$

• Option 3)

$C_3A_4$

• Option 4)

$C_4A_3$

Views

Option 3

Anions: No of ions per unit in HCP = 6

Cations: No of octahedral voids in HCP = 6

So, 75% of 6 = 4.5

$C_{4.5}A_6 = C_3A_4$

Option 1)

$C_2A_3$

Option 2)

$C_3A_2$

Option 3)

$C_3A_4$

Option 4)

$C_4A_3$

Exams
Articles
Questions