A compound is formed by cation C and anion A. The Anions form hexagonal close packed lattice and the cations occupy 75% of the octahedral void. The formula of the compound is

  • Option 1)

    C_2A_3

  • Option 2)

    C_3A_2

  • Option 3)

    C_3A_4

  • Option 4)

    C_4A_3

Answers (1)

Option 3

Anions: No of ions per unit in HCP = 6

Cations: No of octahedral voids in HCP = 6

                        So, 75% of 6 = 4.5

    C_{4.5}A_6 = C_3A_4


Option 1)

C_2A_3

Option 2)

C_3A_2

Option 3)

C_3A_4

Option 4)

C_4A_3

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