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Hydrogen atom in ground state is excited by a monochromatic radiation of \lambda = 975 \AA. Number of spectral lines in the resulting spectrum emitted will be:

  • Option 1)

    3

  • Option 2)

    2

  • Option 3)

    6

  • Option 4)

    10

 

Answers (1)

best_answer

@8762

\lambda -975 A^{o}

\therefore Energy associated with it =  \frac{12400}{975}ev

=12.7^{o}ev

\Delta E=13.6 \left( \frac{1}{m^{2}} - \frac{1}{n^{2}}\right )\:\:\:\:\: Or, \:\:\:\:\:12.70=13.60 \left( 1- \frac{1}{n^{2}} \right )

Or, \:\: 1- \frac{1}{n^{2}}= \frac{12.70}{13.60}\:\:\:\:\Rightarrow n=4
So total number of spectral line will be = \frac{n(n-1)}{2}=\frac{4 \times 3}{2}=6


Option 1)

3

This option is incorrect.

Option 2)

2

This option is incorrect.

Option 3)

6

This option is correct.

Option 4)

10

This option is incorrect.

Posted by

divya.saini

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