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The hybridization involved in complex \left [ Ni \left ( CN \right )_{4} \right ]^{2-}is.(At.No.Ni=28)

  • Option 1)

    dsp^{2}

  • Option 2)

    sp^{3}

  • Option 3)

    d^{2}sp^{2}

  • Option 4)

    d^{2}sp^{3}

 

Answers (1)

best_answer

As we learnt in 

Hybridisation -

The process of mixing of atomic orbitals belonging to the same atoms of slightly different energies so that a redistribution of energy takes place between them  resulting in the formation of new set of orbital of equivalent energies and shape is called hybridisation.

- wherein

The new orbitals thus formed are called hybrid orbitals

 

 In \left [ Ni(CN) _{4}\right ]^{2-}, N\:is\:in +2\ O.S.

    Ni^{2+}:\left [ A_{r} \right ]3d^{8}48^0

or we could write 

Since, CN- is a strong field ligand, so the electrons will pair up and hybridisation will be dsp2


Option 1)

dsp^{2}

This solution is correct 

Option 2)

sp^{3}

This solution is incorrect 

Option 3)

d^{2}sp^{2}

This solution is incorrect 

Option 4)

d^{2}sp^{3}

This solution is incorrect 

Posted by

Aadil

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