A source S_{1} is producing, 10^{15} photons per second of wavelength 5000 A^{\circ}. Another source S_{2} is producing 1.02\times 10^{15} photons per second of wavelength 5100 A^{\circ} Then, (power of S_{2}) (power of S_{1}) is equal to:

  • Option 1)

    1.00

  • Option 2)

    1.02

  • Option 3)

    1.04

  • Option 4)

    0.98

 

Answers (1)
D Divya Saini

As we discussed in concept

photon -

A packet or bundle of energy is called a photon

-

 

 and

Energy of a photon -

\fn_jvn E= h\nu = \frac{hc}{\lambda }

- wherein

h= Plank's\: constant

\boldsymbol{\nu= frequency\: of \: radiation }

\lambda \rightarrow wave \: length

 

 Power = N\:=\frac{hc}{\lambda}

\frac{P_{2}}{P_{1}}=\frac{\frac{N_{1}}{\lambda_{1}}}{\frac{N_{2}}{\lambda_{2}}}\:=\: \frac{N_{2} \lambda_{2}}{N_{2} \lambda_{1}} = \frac{10^{15}\times 5100\times 10^{-10}}{1.02\times 10^{15}\times 5000\times 10^{10}}

\frac{P_{2}}{P_{1}}\:=\:\frac{5100}{5100}\:=\:1

 

 

 


Option 1)

1.00

This option is correct.

Option 2)

1.02

This option is incorrect.

Option 3)

1.04

This option is incorrect.

Option 4)

0.98

This option is incorrect.

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