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  • Solve it, - Dual Nature of Matter and Radiation - NEET-2

A source S_{1} is producing, 10^{15} photons per second of wavelength 5000 A^{\circ}. Another source S_{2} is producing 1.02\times 10^{15} photons per second of wavelength 5100 A^{\circ} Then, (power of S_{2}) (power of S_{1}) is equal to:

  • Option 1)

    1.00

  • Option 2)

    1.02

  • Option 3)

    1.04

  • Option 4)

    0.98

 

Answers (1)

best_answer

As we discussed in concept

photon -

A packet or bundle of energy is called a photon

-

 

 and

Energy of a photon -

\fn_jvn E= h\nu = \frac{hc}{\lambda }

- wherein

h= Plank's\: constant

\boldsymbol{\nu= frequency\: of \: radiation }

\lambda \rightarrow wave \: length

 

 Power = N\:=\frac{hc}{\lambda}

\frac{P_{2}}{P_{1}}=\frac{\frac{N_{1}}{\lambda_{1}}}{\frac{N_{2}}{\lambda_{2}}}\:=\: \frac{N_{2} \lambda_{2}}{N_{2} \lambda_{1}} = \frac{10^{15}\times 5100\times 10^{-10}}{1.02\times 10^{15}\times 5000\times 10^{10}}

\frac{P_{2}}{P_{1}}\:=\:\frac{5100}{5100}\:=\:1

 

 

 


Option 1)

1.00

This option is correct.

Option 2)

1.02

This option is incorrect.

Option 3)

1.04

This option is incorrect.

Option 4)

0.98

This option is incorrect.

Posted by

divya.saini

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