Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape?

  • Option 1)

    1/8

  • Option 2)

    1/4

  • Option 3)

    3/8

  • Option 4)

    1/2

 

Answers (1)

As we learned in concept

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

 

 By  graham's law of diffusion of gas

\frac{r_{1}}{r_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}

\frac{r_{H_{2}}}{r_{O_{2}}}=\sqrt{\frac{32}{2}}=4

\frac{0.5}{r_{O_{2}}}=4

{r_{O_{2}}}=\frac{1}{8}


Option 1)

1/8

Option is correct

Option 2)

1/4

Option is incorrect

Option 3)

3/8

Option is incorrect

Option 4)

1/2

Option is incorrect

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