A bubble of air is underwater at temperature 15^{o}C and the pressure 1.5bar. If the bubble rises to the surface where the temperature is 25^{o}C and the pressure is 1.0 bar, What will happen to the volume of the bubble?

  • Option 1)

    Volume will become greater by a factor of 1.6

  • Option 2)

    Volume will become greater by a factor of 1.1

  • Option 3)

    Volume will become smaller by a factor of 0.70

  • Option 4)

    Volume will become greater by a factor of 2.5

 

Answers (1)
D Divya Saini

 

Ideal Gas Law -

PV=nRT

- wherein

P - Pressure

V - Volume

n - No. of Moles

R - Gas Constant

T - Temperature

 

 We know that from ideal gas equation V \propto\frac {I}{p}

given T_{1} = 273+15 K= 288K, P_{1} = 1.5 b\:ar

T_{2} = 25 + 273 K = 293 K, P_{2} = 1\: bar

V_{1} \propto \frac{288}{1.5} V_{1} \propto 192

V_{2} \propto \frac{293}{1}

=>\frac{V_{2}}{V_{1}} = \frac {298}{192} = 1.55=1.6


Option 1)

Volume will become greater by a factor of 1.6

This is correct answer

Option 2)

Volume will become greater by a factor of 1.1

This is incorrect answer

Option 3)

Volume will become smaller by a factor of 0.70

This is incorrect answer

Option 4)

Volume will become greater by a factor of 2.5

This is incorrect answer

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