Q&A - Ask Doubts and Get Answers
Q

Solve this problem An electric dipole is placed at an angle of 30° with an electric field intensity2 x 105 N/C. It experiences a torque equal to 4 N m. The charge on thedipole, if the dipole length is 2 cm, is

An electric dipole is placed at an angle of 30° with an electric field intensity 2 x 105 N/C. It experiences a torque equal to 4 N m. The charge on the dipole, if the dipole length is 2 cm, is

  • Option 1)

    8 mC

  • Option 2)

    2 mC

  • Option 3)

    5 mC

  • Option 4)

    7 \muC

 
Answers (1)
557 Views
V Vakul

As we discussed in

Torque Experienced by the dipole -

vec{	au }=vec{P}	imes vec{E}

vec{	au }=PEsin Theta

Theta =0^{circ}    	au =0

Theta =frac{pi }{2}             	au = max^{m}

- wherein

 

 T=PESin\theta\:\:\:\:\:\:=> (ql)ESin\theta

 

q=\frac{T}{ElSin\theta}\:\:\:\:\:=\frac{4}{2\times10^{5}\times0.02\times\frac{1}{2}}

\frac{4}{2\times10^{3}}=2\times10^{-3}=2mC

 


Option 1)

8 mC

This option is incorrect.

Option 2)

2 mC

This option is correct.

Option 3)

5 mC

This option is incorrect.

Option 4)

7 \muC

This option is incorrect.

Exams
Articles
Questions