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  • Solve this problem In which of the following pairs, both the species are not isostructural?

In which of the following pairs, both the species are not isostructural?

  • Option 1)

    SiCl_{4}, PCl^{+}_{4}

  • Option 2)

    Diamond, silicon carbide

  • Option 3)

    NH_{3}, PH_{3}

  • Option 4)

    XeF_{4}, XeO_{4}

 

Answers (1)

As we learnt in 

Dettermination of shape of molecules using VSEPR Theory -

calculate \:X

X=(No.\;of\:valence\:electrons\:of\:central\:atom\:)+(No.\:of\:other\:atom\:)+(Negative\:charge\:on\:the\:molecule)-(Positive\:charge\:on\:the\:molecule)

-

 

 

Shape of molecules -

-

 

 H=\frac{1}{2}\left [ V+M-C+A \right ]

V = No. of valence electrons

M = No. of surrounding monavalent atoms 

C = cationic charge 

A = anionic charge 

In XeF_{4},\ H=\frac{1}{2}\left (8+4+0-0 \right )=6, sp3d2 hybridization.

In XeO_{4},\ H=\frac{1}{2}\left (8+0+0-0 \right )=4, sp3 hybridization

\therefore X_{e}F_{4} is square planar, whereas XeO4 is tetrahedrol.

 


Option 1)

SiCl_{4}, PCl^{+}_{4}

This solution is incorrect 

Option 2)

Diamond, silicon carbide

This solution is incorrect 

Option 3)

NH_{3}, PH_{3}

This solution is incorrect 

Option 4)

XeF_{4}, XeO_{4}

This solution is correct 

Posted by

Vakul

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