It is because of inability of ns2 electrons of the valence shell to participate in bonding that :

  • Option 1)

    Sn2+ is reducing while Pb4+ is oxidising

  • Option 2)

    Sn2+ is oxidising while Pb4+ is reducing

  • Option 3)

    Sn2+ and Pb2+ are both oxidising and reducing

  • Option 4)

    Sn4+ is reducing while Pb4+ is oxidising

 

Answers (1)

As we discussed in concept ID

Inert pair effect -

The phenomenon in which outer shell s electrons (ns2) penetrate to (n-1) d-electrons and thus become closer to nucleus and are more effectively pulled by the nucleus

- wherein

This results in less availability of ns2 electrons pair for bonding or ns2 electron pair becomes inert.

 

  Stability of S_{n}^{+4}> S_{n}^{2+}  but stability of P_{b}^{2+}> P_{b}^{+4}  which result S_{m}^{2+}  is reducing while P_{b}^{+4}  is oxidising in nature.


Option 1)

Sn2+ is reducing while Pb4+ is oxidising

Correct option

Option 2)

Sn2+ is oxidising while Pb4+ is reducing

Incorrect option

Option 3)

Sn2+ and Pb2+ are both oxidising and reducing

Incorrect option

Option 4)

Sn4+ is reducing while Pb4+ is oxidising

Incorrect option

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