# The displacement of a particle executing simple harmonic motion is given by $y = A _ 0 + A \sin \omega t + B \ cos \omega t$ Then the amplitude of its oscillation is given by : Option 1)$A _0 + \sqrt{ A^2 + B^2 }$Option 2)$\sqrt{ A^2 + B^2 }$Option 3)$\sqrt{A_0 ^2+ (A + B)^2 }$Option 4)A+ B

The particle execute SHM about its center at $\alpha = A_0 \\\\ amplitude = \sqrt { A^2 + B^2 }$

Option 1)

$A _0 + \sqrt{ A^2 + B^2 }$

Option 2)

$\sqrt{ A^2 + B^2 }$

Option 3)

$\sqrt{A_0 ^2+ (A + B)^2 }$

Option 4)

A+ B

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