A gaseous mixture was prepared by taking equal mole of CO_{2}\ and\ N_{2} . If the total pressure of the mixture was found 1 atmosphere, the partial pressure of the nitrogen \left ( N_{2} \right ) in the mixture is:

  • Option 1)

    0.5 atm

  • Option 2)

    0.8 atm

  • Option 3)

    0.9 atm

  • Option 4)

    1 atm

 

Answers (1)
P Plabita

 

Partial Pressure of a gas in gaseous mixture -

Partial Pressure = (Total Pressure of Mixture) \times (mole fraction of gas)

 

-

 

 P_{N2}=\frac{Qn_{N2}}{n_{N2+n_{o2}}}.P=(\frac{1}{2}).1\:atm=\frac{1}{2}\:atm

P_{N2}=0.5\:atm


Option 1)

0.5 atm

This solution is correct 

Option 2)

0.8 atm

This solution is incorrect 

Option 3)

0.9 atm

This solution is incorrect 

Option 4)

1 atm

This solution is incorrect 

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