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  • Solve this problem Two thin dielectric slabs of dielectric constants K1and K2(K1< K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field E between the plates with distance

Two thin dielectric slabs of dielectric constants K1 and K2 (K1 < K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field "E" between the plates with distance "

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

Answers (1)

best_answer

As we learnt in 

Dielectric Constant (K) -

K=\frac{E}{{E}'}

 

- wherein

K is also known as relative permittivity \left (\varepsilon _{r} \right ).

 

 Electric field in dielectric decreases and outside it is higher.comparing dielectric 1 and 2 electric fields is smaller in a dielectric  2\left ( \because k_{2}> k_{1} \right )


Option 1)

Incorrect

Option 2)

Incorrect

Option 3)

Incorrect

Option 4)

Correct

Posted by

Aadil

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