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  • statement-1 : Balmer series lies in the visible region of electromagnetic spectrum. statement-2 :   <img alt="\frac{1}{\lambda}=\mathrm{R}\left

statement-1 : Balmer series lies in the visible region of electromagnetic spectrum.

statement-2 :   \frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{2^2}-\frac{1}{\mathrm{n}^2}\right] \text {, where } \mathrm{n}=3,4,5 \text {, }

 

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

The wavelength in Blamer series is given by

\begin{aligned} & \frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{2^2}-\frac{1}{\mathrm{n}^2}\right], \mathrm{n}-3,4,5, \ldots \ldots . \\ & \frac{1}{\lambda_{\max }}=\mathrm{R}\left[\frac{1}{2^2}-\frac{1}{3^2}\right] \\ & \frac{1}{\lambda_{\max }}=\frac{36}{5 \mathrm{R}}=\frac{36}{5 \times 1.097 \times 10^7}=6563 \mathrm{~A} \end{aligned}

\begin{aligned} & \text { and } \frac{1}{\lambda_{\max }}=\mathrm{R}\left[\frac{1}{2^2}-\frac{1}{\infty^2}\right] \\ & \lambda_{\max }=\frac{4}{\mathrm{R}}=\frac{4}{1.097 \times 10^7}=3646 \mathrm{~A} \end{aligned}

The wavelength 6563 A and 3646A lie in visible region. Therefore., Blamer series lies in visible region.

Posted by

Ramraj Saini

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