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# Stuck here, help me understand: A rod of weight wis supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. T

A rod of weight w is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is:

• Option 1)

• Option 2)

• Option 3)

• Option 4)

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$By \ Equating \ forces . \\N_1+N_2=W \\ Equating \ Torques \ about \ A \\ Wx=N_2d =>\\N_2=Wx/d \\So N_1=W[1- (x/d)] \\.�. \ Normal \ reaction \ on \ A \ is \ W[1- (x/d)]$

Option 1)

Option 2)

Option 3)

Option 4)

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