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  • Stuck here, help me understand: - d and f Block Elements - NEET

In acidic medium, H_{2}O_{2} changes Cr_{2}O_{7}^{-2} to CrO_{5} which has two (-O-O) bonds. Oxidation state of Cr in CrO_{5} is:-

  • Option 1)

    +5

  • Option 2)

    +3

  • Option 3)

    +6

  • Option 4)

    -10

 

Answers (1)

best_answer

 

Exceptional configuration in '3d' series -

Due to half fill stable configuration 24^{Cr} is stable in 3d^{5}\:4s^1 configuration at the place of 3d^{4}\:4s^2.
Similarly, 29^{Cu} stable with 3d^{10}4s^1 at the place of 3d^{9}4s^2.

-

 

 The reaction proceeds as follows:

Cr_{2}O_{7}^{2-}+2H^{+}+4H_{2}O_{2}\rightarrow 2CrO\left ( O_{2} \right )_{2}+5H_{2}O

In peroscide linkages, the ascidation state of each axygen atom is -1. Let O.S. of be x

Then, x-2-2*2=0

= x=+6

O.S, is +6


Option 1)

+5

This is incorrect option

Option 2)

+3

This is incorrect option

Option 3)

+6

This is correct option

Option 4)

-10

This is incorrect option

Posted by

Aadil

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