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  • Stuck here, help me understand: Lithium has a bcc structure. Its density is 530 kg m-3 and its atomic mass is 6.94g mol-1. Calculate the edge lenth of a unit cell of Lihium metal. (NA = 6.02 x 1023 mol-1)

Lithium has a bcc structure. Its density is 530 kg m-3 and its atomic mass is 6.94g mol-1. Calculate the edge lenth of a unit cell of Lihium metal. (NA = 6.02 x 1023 mol-1)

  • Option 1)

    154 pm

  • Option 2)

    352 pm

  • Option 3)

    527 pm

  • Option 4)

    264 pm

 

Answers (1)

best_answer

As we learnt in 

Density of cubic unit cell -

d = \frac{zM}{a^3N_o}

 

- wherein

Where,

d = density of crystal

z = no. of effective constituent particles in one unit cell

M = molecular weight

a = edge length of unit cell

No = 6.022*1023

 

Density of cubic unit cell

d=\frac{zM}{a^{3}N_{o}}

a=\left ( \frac{zM}{dN_{o}} \right )^{\frac{1}{3}}

=\left ( \frac{2\times 6.94}{0.530g\times 6.02\times 10^{23}} \right )^{\frac{1}{3}}

=3.52\times 10^{-10}\: m

=352\: pm


Option 1)

154 pm

Option is incorrect

Option 2)

352 pm

Option is correct

Option 3)

527 pm

Option is incorrect

Option 4)

264 pm

Option is incorrect

Posted by

Aadil

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