Under isothermal condition, a gas at 300K expands from 0.1L to 0.25L against a constant external pressure of 2 bar. The work done by the gas is:

[Given that 1L bar = 100 J]

  • Option 1)

    -30 J

  • Option 2)

    5 kJ

  • Option 3)

    25 J

  • Option 4)

    30 J

Answers (1)

We know that the work done is given as:

W = -P\Delta V

Now,

P_{at} = 2 bar

V_i = 0.1 L

V_f = 0.25 L

\therefore W = - 2bar (0.25 - 0.1) \\\Rightarrow W = -2\times 0.15 \\\Rightarrow W = -0.30 L bar \\\Rightarrow W = -30 J

Option 1 is correct.


Option 1)

-30 J

Option 2)

5 kJ

Option 3)

25 J

Option 4)

30 J

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