Get Answers to all your Questions

header-bg qa

A coil has resistance 30 ohm and inductive reactance 20 ohm at 50Hz frequency. If an ac source, of 200volt, 100Hz, is connected across the coil, the current in the coil will be

  • Option 1)

    4.0A

  • Option 2)

    8.0A

  • Option 3)

    \frac{20}{\sqrt{13}}A

  • Option 4)

    2.0A

 

Answers (1)

best_answer

 

Inductive reactance (XL) -

Opposition offered by inductive circuit.

 

- wherein

X_{L}= omega L= 2pi 
u L


u _{dc}=0        X_{L}=0

 

 Inductive reactance =\omega L

a+50Hz, X_{L}=20\Omega

Then at 100Hz, X_{L}=20\Omega , \ R=30\Omega

\therefore Z=\sqrt{R^{2}+X_{L}^{2}}=50\Omega

\therefore I=\frac{V}{Z}=\frac{200v}{500}=4A


Option 1)

4.0A

This is correct option

Option 2)

8.0A

This is incorrect option

Option 3)

\frac{20}{\sqrt{13}}A

This is incorrect option

Option 4)

2.0A

This is incorrect option

Posted by

Plabita

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks