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  • The binding energy per nucleon in deuterium and helium nuclei are 1.1  and 7.0 <img alt="MeV" src="https://learn.

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV respectively. when two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

Option: 1

30.2 MeV


Option: 2

23.6 MeV


Option: 3

2.2 MeV


Option: 4

28.0MeV


Answers (1)

 

energy mass equivalence -

Delta E=Delta m.c^{2}       

- wherein

Delta m = mass defect

Delta E = energy released

 

 

 _{1}^{2}\textrm{D} + _{1}^{2}\textrm{D} \rightarrow _{2}^{4}\textrm{He} + Q

Q=E(_{2}^{4}\textrm{He})-E(2\ \times\ _{1}^{2}\textrm{D})

Q=7*4-2(2*1.1) = 23.6\ eV

 

Posted by

Sumit Saini

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