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  • The coefficient of apparent expansion of mercury in a glass vessel is 153 X 10-6 / 0C and in a steel vessel is 144 X 10 -6/ 0C. If <img alt="\alpha"

The coefficient of apparent expansion of mercury in a glass vessel is 153 X 10-6 / 0C and in a steel vessel is 144 X 10 -6/ 0C. If \alpha for steel is 12 X 10 -6 / 0C, then for that of the glass is

 

Option: 1

9 \times 10^{-6} /{ }^{\circ} \mathrm{C}


Option: 2

-6 \times 10^{-6} /{ }^{\circ} \mathrm{C}


Option: 3

36 \times 10^{-6} /{ }^{\circ} \mathrm{C}


Option: 4

27 \times 10^{-6} /{ }^{\circ} \mathrm{C}


Answers (1)

best_answer

As we learned

Real Expansion -

\gamma_{real}=\gamma_{apparent}+\gamma_{vessel}

-

\gamma _{real}= \gamma _{app}+\gamma _{vessel}

So \left ( \gamma _{app}+\gamma _{vessel} \right )_{glass}= \left ( \gamma _{app}+\gamma _{vessel} \right )_{steel}

153\times 10^{-6}+\gamma _{vessel,glass}= 144\times 10^{-6}+\gamma _{vessel,steel}

\gamma _{vessel,steel}= 3\alpha = 3\times 12\times 10^{-6}/^{\circ}C\\* =36\times 10^{-6}/^{\circ}C

153\times 10^{-6}+\gamma _{vessel,glass}= 144\times 10^{-6}+36\times 10^{-6}

\gamma _{vessel,glass}=9\times 10^{-6}

 

Posted by

Deependra Verma

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